Question

The foot of a ladder is 6 m away from a wall and its top reaches a window 8 m above
the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall.
to what height does its top reach?​

Answer 1

Answer:

6m

Step-by-step explanation:

We know here that height of ladder will always be constant.

height of top position from ground=8m

height of bottom from wall=6m

height of ladder =

$\sqrt{8 {}^{2} +6 {}^{2} } = 10$

Now height of ladder from ground=6m

distance of bottom from ground=√(10²-8²)=6

Answer 2

Given:-

• The length of AB = 6cm.
• Length of BC = 8cm

To find:-

• Find the length of the ladder and if it's foot is 8m away from the wall. what does its top reach.?

Solutions:-

• Triangle ABC is a right angled triangle.

By using Pythagoras theorem;

=> h² = p² + b²

=> (AB)² = (BC)² + (AB)²

=> x² = 8² + 6²

=> x² = 64 + 36

=> x² = 100

=> x = √100

=> x = 10cm

The length of ladder is 10cm.

The foot of the ladder is 8m away from the wall.

• AC = 10cm
• AB = 8cm
• BC = ycm

By using Pythagoras theorem;

=> (AC)² = (AC)² + (AB)²

=> (10)² = (y)² + (8)²

=> 100 = y² + 64

=> 100 - 64 = y²

=> 36 = y²

=> √36 = y

=> y = 6cm

Hence, the length of ladder is 10cm and it the foot of the ladder is 8cm away from the wall it is height is 6cm.