ThE FOOT OF A LADDER IS 6M AWAY FROM A WALL AND ITS TOP REACHES A WINDOW 8M ABOVE THE GROUND. IF THE LADDER IS SHIFTED IN SUCH A WAY THAT ITS FOOT IS 8M AWAY FROM THE WALL,TO WHAT HEIGHT DOES ITS TOP REACH
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79
initial case
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base = 6 m
altitude = 8m
length of ladder = hypotenuse = ?
hyp = √ a² + b²
= √6² + 8²
=√100
=10 m
∴ length of ladder is 10 m
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case 2
base = 8 m
hyp = length of ladder = 10maltitude = ?
hyp= √ a² + b²
a = √ 10² - 8²
a = √100 - 64
a = √ 36
a=6 m
it will reach the height 6 m above the ground
----------------------
base = 6 m
altitude = 8m
length of ladder = hypotenuse = ?
hyp = √ a² + b²
= √6² + 8²
=√100
=10 m
∴ length of ladder is 10 m
--------------
case 2
base = 8 m
hyp = length of ladder = 10maltitude = ?
hyp= √ a² + b²
a = √ 10² - 8²
a = √100 - 64
a = √ 36
a=6 m
it will reach the height 6 m above the ground
Answered by
59
Solution with diagram is attached below... Plz refer attachment
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