Question

The foot of perpendicular from -2,5 in y+ 3=0 is

Answer 1

SOLUTION

TO DETERMINE

The foot of perpendicular from (-2,5) in the line y + 3 = 0

EVALUATION

Here the given equation of the line is

y + 3 = 0

Now we have to find the foot of perpendicular from (-2,5) in y + 3 = 0

Now for any point on the line y + 3 = 0 , the ordinate of the point is - 3

Thus the required point is of the form ( k , - 3)

Next the equation of the line perpendicular to y + 3 = 0 is x + c = 0

Now the line x + c = 0 goes through the point (-2,5)

Consequently c = 2

So the perpendicular equation becomes x + 2 = 0

Now the lines x + 2 = 0 & y + 3 = 0 intersects at the point ( - 2, - 3)

Hence the required foot of the perpendicular = ( - 2 , - 3 )

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