the foot of the ladder rests againsrt a wall and its top is held by a tie rop as shown in the figure below. the ladder weighs 1000N, and centre of gravity os 0.40m length from the foot .a 150N child hangs from a rung that is 0.20 of length from thr top. determine the tension in the tie rope and the components of the force on the foot of the ladder
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Correction : Ladder weighs 100N
Completing Question :
Length of ladder 1m
Angle made by ladder with the vertical is 37°.
Final Answer :
T=120N
Horizontal Component of force acting on the foot of ladder : = Tension of rope =120N
Vertical Component : 250N
Steps and Understanding :
1) System is in Equilibrium,
So Net Torque about any point is 0 .
2) Let that point be Foot of ladder.
There are forced which are giving torque to ladder.
Tension
Force applied by Child
Gravitational force.
3) We will make out ne+ torque 0 to find the value of Tension.
For Calculation see pic.
Completing Question :
Length of ladder 1m
Angle made by ladder with the vertical is 37°.
Final Answer :
T=120N
Horizontal Component of force acting on the foot of ladder : = Tension of rope =120N
Vertical Component : 250N
Steps and Understanding :
1) System is in Equilibrium,
So Net Torque about any point is 0 .
2) Let that point be Foot of ladder.
There are forced which are giving torque to ladder.
Tension
Force applied by Child
Gravitational force.
3) We will make out ne+ torque 0 to find the value of Tension.
For Calculation see pic.
Attachments:
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