The foot of the perpendicular from P(-3,2) to Y-axis is M. Coordinates of M are .....,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) (3, 0)
(b) (0, 2)
(c) (3/2,-1)
(d) (-3, 2)
Answers
Answered by
23
The foot of perpendicular from P(-3, 2) to Y-axis is M.
we know,product of slope of two perpendicular lines = -1
slope of MP × slope of Y-axis = -1
Let M = (x, y)
slope of MP = (y - 2)/(x + 3)
slope of Y - axis = 1/0
now, (y - 2)/(x + 3) × 1/0 = -1
(y - 2) × 1 = -1 × (x + 3) × 0
y - 2 = 0
y = 2
hence, point M = (x , 2) where
therefore, (b) and (d) both are correct.
we know,product of slope of two perpendicular lines = -1
slope of MP × slope of Y-axis = -1
Let M = (x, y)
slope of MP = (y - 2)/(x + 3)
slope of Y - axis = 1/0
now, (y - 2)/(x + 3) × 1/0 = -1
(y - 2) × 1 = -1 × (x + 3) × 0
y - 2 = 0
y = 2
hence, point M = (x , 2) where
therefore, (b) and (d) both are correct.
Answered by
28
According to the problem given ,
Coordinates of P ( -3 , 2 )
PM is perpendicular to Y - axis .
PM intersects Y - axis at M.
coordinates of M ( 0 , 2 )
Therefore ,
Option ( b ) is correct.
I hope this helps you.
: )
Coordinates of P ( -3 , 2 )
PM is perpendicular to Y - axis .
PM intersects Y - axis at M.
coordinates of M ( 0 , 2 )
Therefore ,
Option ( b ) is correct.
I hope this helps you.
: )
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