Question

The football player kicked a ball from the ground with initial speed 213 ms2 at the angle of 45 degree. an other player which is 35m away in direction of kick starts. do most the ball at that instant. what will be the average speed of he meet the ball, just before it hit the ground?

Answer 1

Answer:

Although we could use Equation to find where it lands, we choose instead to work with Equation and Equation (for the soccer ball) since these will give information about where and when and these are also considered more fundamental than Equation. With Δy=0,

we have

Δy=(v

0

sinθ

0

)t−

2

1

gt

2

⇒t=

(9.8m/s

2

)/2

(19.5m/s)sin45.0

0

=2.81s

Then Eq yields Δx=(v

0

cosθ

0

)t=38.7m. Thus, using Eq., the player must have an average velocity of

v

avg

=

Δt

Δ

r

=

2.81s

(38.7m)

i

^

−(55m)

j

^

=(−5.8m/s)

i

^

which means his average speed (assuming he ran in only one direction) is 5.8m/s.