Question

the for the taxi fare in a town is 102 tor first kilometers and 62 for kilometers Subsequent distance and total fare Taking distance as write the inequation for data. what is total fare for 15 km. 9 . x fare y this . write the linear equation for this data. what is the total fare for 15 km?​

Answer 1

Answer:

Taxi fare for first kilometer = Rs. 10

Taxi fare for subsequent distance = Rs. 6

Total distance covered = x

Total fare = y

Since the fare for first kilometer = Rs. 10

According to problem,

Fare for (x - 1) kilometer = 6(x-1)

So, the total fare = 6(x-1) + 10

y = 6(x-1) + 10

y = 6x - 6 + 10

y = 6x + 4

Hence, y = 6x + 4 is the required linear equation.

Answer 2

Answer:

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Step-by-step explanation:

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13

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