Question

The force 10-5N acts on a charge of 5µC, Then the electric field intensity is​

Answer 1

Answer:

Electric field    E=qF

Or    E=5×10−610×10−4=200 N/C

Answer 2

Answer:

the magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation E = kQ/r2, where k is a constant with a value of 8.99 x 109 N m2/C2.

Explanation:

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