Question

The force acting on a body of mass 5 kg is (3i+4j)N. The magnitude of the acceleration of the body is -

(A) 0.2 ms–2

(B) 1 ms–2

(C) 1.4 ms–2

(D) 5m^-2​

Answer 1

Answer:

acceleration is 1 ms-2

Explanation:

F = √3²+4² = √25 = 5 , m = 5 kg    

by Newton's 2nd law of motion F = ma  and a = F/m = 5/5 = 1

Answer 2

Answer:

• The acceleration of the body is 1 m/s².

Given:

1. Mass of the body (M) = 5 Kg
2. Force Applied (F) = 3 i + 4 j

Explanation:

$\rule{300}{1.5}$

Firstly finding the Magnitude of the force,

⇒ F = √ (F_x)² + (F_y)²

Where,

• F Denotes the magnitude of the force.
• F_x Denotes Horizontal component.
• F_y Denotes Vertical component.

Now,

⇒ F = √ (F_x)² + (F_y)²

Substituting the values,

⇒ F = √ (3)² + (4)²

⇒ F = √ 9 + 16

⇒ F = √ 25

⇒ F = 5

⇒ F = 5 N.

∴ We got the magnitude of the Force.

$\rule{300}{1.5}$

$\rule{300}{1.5}$

From Newton's second law of motion,

⇒ F = M a

Where,

• F Denotes Force.
• M Denotes Mass.
• a Denotes Acceleration.

Now,

⇒ F = M a

Substituting the values,

⇒ 5 N = 5 Kg × a

⇒ 5 = 5 × a

⇒ a = 5 / 5

⇒ a = 1

⇒ a = 1 m/s²

∴ The acceleration of the body is 1 m/s².

$\rule{300}{1.5}$