Question

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The force applied to a conductor is 10N if the charge in the conductor is
5C, what is the electric field intensity?
a) 10V/m
b) 2V/m
c) 3V/m
d) 15V/m​

Answer 1

Answer:

Explanation:

Explanation: The formula for electric filed density is: D=epsilon*E = 1*8.85*10-12 = 8.85*10-12C /m2

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Answer 2

Concept:

• We have to understand electric field intensity as a function of force and charge
• Forces and charges

Given:

• Force applied to a conductor = 10 N
• Charge in the conductor = 5 C

Find:

• The electric field intensity of the conductor

Solution

We know that the force and charge affect the value of the electric field intensity.

Electric field intensity is actually the amount of force per unit charge.

E = F/Q

where E is the electric field intensity, F is the force, and Q is the charge on the conductor.

F = 10 N, Q = 5 C

E = 10 N/5 C = 2 V/m

The correct option is b) 2 V/m. The electric field intensity is 2V/m.

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