Question

the force between charges of +3C +8C is 8.4N if the distance between charges is doubled the force bretween charges will become

Answer 1

if the distance between charges is doubled then force bretween charges will become one-fourth of initial

Explanation:

F= (k q¹.q²)/r²

where q¹&q² are charges

q¹=+3C

q²=+8C

k= 9*10^9 Nm²/C²

r= distance between charges

give F=8.4N

if distance between charges is doubled

R=2r

R

» F' = (k q¹.q²)/R²

> F' = (k q¹.q²)/(2r) ²

> F' = (k q¹.q²)/4r²

> F' = 1/4 {(k q¹.q²)/r²}

> {(k q¹.q²)/r²}............is F

» F' = 1/4 F

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