Question

the force between the electron in the first Bohr orbit and the nucleus (proton in hydrogen atom is F, then the force between them when the electron is in the second orbit is

Answer 1

Answer:

F/4

Explanation:

r1 = 0.0529 x 1^2/1

f  = k * e^2/r1 = >  ke^2/0.0529

 

for 2nd orbit,

r2 = 0.0529 x 2^2/1) = > 0.0529 x 4

F =ke^2/(0.0529 x 4)

Divide,

F/f we get, =>

F/f = (ke^2/(0.0529 x 4)) *(0.0529/ke^2)) = > ¼

f = 4F

or

F = f/4

Answer 2

Answer:

f/16

Explanation:

dusre ko puchh lo mujhe time nahi hai