Question

the force between two chages each of 10microC is balanced by the weight of 10kg.find the distance between the charges.

Answer 1

Please verify this answer... If it is right?

Answer 2

Answer:

The force between two charges each of 10microC is balanced by the weight of 10kg, the distance between the charges is 0.09m

Explanation:

• The electrostatic force between two charges $q_{1}$ and $q_{2}$ separated by a distance $r$ is given by  $F=K\frac{q_{1} q_{2} }{r^{2} }$

        where $K=9*10^{9}$

• The weight of a body is the gravitational force due to mass, that is $W=mg$

       where the acceleration due to gravity $g=9.8m/s^{2}$

From the question, we have

the charges $q_{1} =q_{2} =10*10^{-6}C$

mass of the body $m=10kg$

weight of the body $W=10*9.8=98N$

the electrostatic force is balanced by the weight of the body

⇒

$K\frac{q_{1} q_{2} }{r^{2} }=mg$

⇒

$\frac{9*10^{9}*10*10^{-6}*10*10^{-6} }{r^{2} } =98\\\frac{9}{980}=r^{2}\\r=0.09m$