the force between two charges 0.06cm apart in 5N . If the changes are moved towards each other by 0.01m then the force between them is
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Answer:
Forces between 2 charges 0.06m apart is 5N
we know, F=
r
2
Kq
1
q
2
S=
(0.06)
2
Kq
1
q
2
Kq
1
q
2
=0.018⟶(1)
F
1
=
[0.06−2(0.01)]
2
Kq
1
q
2
each charge is moved towards the other by 0.04m
F
1
=
(0.04)
2
0.018
F
1
=11.25N
Force will become 11.25 newtons.
Hope it's will help you
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