The force between two charges 0.06m apart is 5 N. If each charge is moved
towards the other by 0.01m, then the force between them will become
(A) 7.20 N
(B) 11.25 N
(C) 22.50 N
(D) 45.00 N
Answers
Answered by
0
Answer:
11.25N
Explanation:
Forces between 2 charges 0.06m apart is 5N
we know, F=
r
2
Kq
1
q
2
S=
(0.06)
2
Kq
1
q
2
Kq
1
q
2
=0.018⟶(1)
F
1
=
[0.06−2(0.01)]
2
Kq
1
q
2
each charge is moved towards the other by 0.04m
F
1
=
(0.04)
2
0.018
F
1
=11.25N
Force will become 11.25 newtons.
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