Question

the force between two charges 0.06m apart is 5N. if the charges are moved towards each other by 0.01m then the force between them is​

Answer 1

Answer:

Explanation:

F=kq1q2/r^2

let kq1q2=m becoz its not changing

case1 : 5=m/(0.06)^2

F=m/(0.01)^2

divide both equations

5/F=1/36

F=180N