Question

The force between two charges in air is "F" the force becomes 3f/5 when placed in a medium at the same distance the electric contains of the medium is​

Answer 1

Answer:

Given that,

The force between two point charges separated by a certain distance is F.

Let us considered q

1

is the first charge particle and q

2

is the second charge particle. r is the distance between the charge particlesq

1

and q

2

.

We know that,

The force is

F=

4πϵ

0

1

r

2

q

1

q

2

If the charges is double and the distance between them is also doubled.

Then, the force will be

F’=

4πϵ

0

1

(2r)

2

2q

1

×2q

2

F=

4

4F

F’=F

The force will be same.

Hence, this is the required solution

Explanation:

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