Question

The Force between two charges when separated by a distance of 50cm in air is 40N.what will be the force between them if distance becomes 25cm​

Answer 1

Answer:

is attached

Explanation:

i hope this helps u

Answer 2

Force will be 160 N

Explanation:

F = Kq₁q₂/r²

• Let F₁ be force at 50 cm & F₂ be the force at 25 cm

F₁/F₂ = Kq₁q₂/(r₁)² / Kq₁q₂/(r₂)²

= (r₂)²/(r₁)²

= (25*25)/(50*50)

= 1/4

4F₁ = F₂

So, force at 25 cm will be 4 times of that at 50

✨ Hence, when distance is 25 the force will be 160N