The force between two point charges in vacuum is 15n, if a brass plate is introduced between the two charges, then force between them will
Answers
Everything of this Question now depends upon the dielectric constant of the brass.
That Question can easily be solved, but after the brass plate came, it becomes little logical.
Brass is an alloy of copper and zinc, and hence, its dielectric constant is approximately tending to the dielectric constant of copper and zinc only.
Thus, We can say that dielectric constant of brass is infinity as that of Copper and zinc.
Now, There is one formula, which is beyond the scope of 11th and 12th class syllabus, But Question was like that, thus we need to use this.
F = 1/4πε₀ × Qq/(r - t + t√k)²
In this formula, ε₀ is the permittivity of the free space, t is the thickness of the medium inserted between charges kept in free space (here brass is inserted.) k is the dielectric constant of Brass which is approximately tending to infinity.
Now, Putting Infinity in k, in this formula, We get,
F = 1/(∞)
F = 0
Thus Force becomes zero between the two charge particles, when Brass is inserted between the two charges.
Hope it helps.
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