Question

The force between two point charges q1 and q2, placed at a distance of r is kept in vacuum and then place in a material medium. How will the force be affected? *
1 point
The force will reduce
The force will increase
The force will remain the same
Haven't yet discovered​

Answer 1

Answer:

Given that,

First charge =q

1

Second charge =q

2

Distance =r

We know that,

According to Coulomb’s law

The force is

F=

4πε

0

1

×

r

2

q

1

q

2

So, the proportionality constant is

=

4πε

0

1

Hence, this is the required solution

Answer 2

Explanation:

first charge =q

1

second charge=q

2

distance is r

answer is 1