The force between two point charges separated by air is 4N.When separated by a medium of relative permittivity 2,the force between them becomes?
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Answer:
2N
Explanation:
F = 1/(4π k∈₀) q₁q₂/r²
F = 1/(4π∈) q₁q₂/r²
when, k = 2.
F' = 1/(4π 2∈₀) q₁q₂/r²
= 1/2 * 1/(4π∈) q₁q₂/r²
= 1/2 * F
= 1/2 * 4N = 2N
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