Question

The force constant of a wire is k and that of the another wire is 3k
when both the wires are stretched through same distance, if work
done are Wa and W2, then
(a) W2 =W1
(b) W2 =9W1
(c) W1=3 W2
(d) W2=3 W1​

Answer 1

Work required = change in energy

W=ΔE

W=  

2

1

​  

kx  

2

 

If both wires are stretched through same distance then W∝k as k  

2

​  

=2k  

1

​  

 so W  

2

​  

=2W  

1

​