Question

The force exerted by an electric field of 10 C at a point is 16×10-4 N what is the intensity of the electric field at the point.

Answer 1

Hey there!

Here, q = 10C

F = 16 × 10^-4

Using the relation,

F = qE

=> E = F/q

=> E = 16 × 10^-4/ 10

=> E = 16 × 10^-3 N/C

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Answer 2

Answer:

E=F/Q  is the formula

Explanation:

therefore

E=16*10^-4/10

=16*10^-5