The force experienced by a proton placed in an upward electric field of 4*10^4NC^-1 is
Answers
Given : A proton is placed in an electric field 4 × 10⁴ N/C directed vertically upward.
To find : The force experienced by the proton.
solution : we know, the electric force experienced by charge q in an electric field E is given by, F = qE
here q = charge on proton = 1.6 × 10^-19 C
E = 4 × 10⁴ N/C
so, F = 1.6 × 10^-19 C × 4 × 10⁴ N/C
= 6.4 × 10^-15 N
Therefore the force experienced by the proton is 6.4 × 10^-15 N
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Given:
Placed proton,
E =
Charge,
q =
To Find:
Force experienced by a proton = ?
Solution:
As we know,
⇒
On putting the estimated values, we get
⇒
⇒
So that the force will be "6.4 × 10⁻¹⁵ N".