Question

The force experienced by a test charge of 2 µC placed in electric field of 5.2 × 10⁶ N/C is:


A) 10.4 × 10¹² N

B) 10.4 × 10⁹ N

C) 10.4 × 10⁶ N

D) 10.4 N​

Answer 1

Answer:

Option D) 10.4 N

Explanation:

Given :

Charge, q = 2 µC

Electric field, E = 5.2 × 10⁶ N/C

To find :

the force experienced by the charge

Solution :

Electric Field is defined as the electric force per unit charge.

  E = F/q

So,

The force experienced by a test charge of q C placed in electric field of E N/C is given by,

 F = Eq

Substituting the values,

F = Eq

⇒ F = 5.2 × 10⁶ × 2 × 10⁻⁶

⇒ F = 5.2 × 2

⇒ F = 10.4 N

∴ The required force experienced by the charge is 10.4 N.