Chemistry, asked by waqas9151737, 3 days ago

the force experienced by a wall on which water strikes normally at a speed of 10ms^-1and at a discharge of 0.0001m^3s^-1 is?​

Answers

Answered by AbhiRajSinghania
0

Explanation:

By Newton’s second law, force over time yields a change in momentum . Let us assume that velocity changes from 10 m/s to zero at the wall, rather than go through a reversal of velocity by shaped deflectors as in a turbine. A volume of water equal to 0.0001 m has a mass of 0.1 kg.

Answered by mirzafardeen82
0

Answer:1 N

Explanation: F = mv/t for Force water exerts on wall. v = 10m/s m/t = 0.0001 (1000)/1 = 0.1kg per sec Therefore, F = 0.1 × 10 F = 1N

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