The force, F newtons (N), between two particles is inversely proportional to
the square of the distance, d m, between them. When the particles are 2 m apart,
the force between them is 10 N. Find
(i) the force between the particles when they are 5 m apart,
(ii) the distance between the particles when the force between them is 25 N.
Answers
Answer:
80 N
Step-by-step explanation:
the force of repulsion, F newtons (N), between two particles is inversely proportional to the square of the distance, D m, between the particles.
when the particles are a certain distance apart, the force of repulsion is 20 N. find the force when the distance is halved
F ∝ 1/D²
=> F = k/D²
Let say at distance = 2x the force of repulsion = 20N
=> 20 = k/(2x)²
=> k = 80x²
F = k/x²
=> F = 80x²/x²
=> F = 80 N
the force when the distance is halved = 80 N
The force between two particles will be 80 N.
GIVEN: The force, F newtons (N), between two particles, is inversely proportional to the square of the distance, d m, between them.
TO FIND: Force between the particles
SOLUTION:
As we are given in the questions,
The force of repulsion, F newtons (N), between two particles is inversely proportional to the square of the distance, D m, between the particles.
when the particles are a certain distance apart, the force of repulsion is 20 N. find the force when the distance is halved
F ∝ 1/D²
F = k/D²
Let say at distance = 2x the force of repulsion = 20N
20 = k/(2x)²
k = 80x²
F = k/x²
F = 80x²/x²
F = 80 N
Therefore,
The force when the distance is halved = 80 N
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