Question

the force in Newton per meter square required to maintain difference of velocity of one meter per second between two parallel layers of the liquid at the distance____​

Answer 1

Answer:

Area=a

2

=1×0.1=0.1m

2

η=0.01poise

η=

10

0.01

=0.001deca poise

dv=0.1m/s

F=0.002N

We know that

As F=ηA

dx

dv

or dx=η

F

Adv

=

0.002

0.001×(0.1)

2

×0.1

=0.0005m