The force is acting at an angle of 60° x-axis if the x-component of the force is 50 N, Find the resultant force and y-component of the force ?
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Answered by
9
Hello Dear.
Here given that Force at x component is 50 N.
Fx= 50 N .
So we have to find the resultant force ,
R = Fx + Fy
Here the resultant direction is 60° from x axis.
∴ Fx = R cos (60°)
50 N = R cos (60°)
50 = R (1/2)
R = 100 N.
So , applying same process.
Fy = R sin(60°)
Where Fy is the force at Y component.
Fy = 100 sin (60°)
Fy = 100 (√3 / 2)
Fy = 86.6 N.
Hence Resultant force R is 100 N & Force at Y component Fy is 86.6 N.
Here given that Force at x component is 50 N.
Fx= 50 N .
So we have to find the resultant force ,
R = Fx + Fy
Here the resultant direction is 60° from x axis.
∴ Fx = R cos (60°)
50 N = R cos (60°)
50 = R (1/2)
R = 100 N.
So , applying same process.
Fy = R sin(60°)
Where Fy is the force at Y component.
Fy = 100 sin (60°)
Fy = 100 (√3 / 2)
Fy = 86.6 N.
Hence Resultant force R is 100 N & Force at Y component Fy is 86.6 N.
Answered by
27
Heya.......!!!
___________________________
- Given in Tye Questions :-
• Angle at which force is acting = 60°
• x - component of force = 50 N
Let x - component of Force be Fx
Let y - component of Force be Fy
Let resultant force be Fr
=> Fx = Fr ( Cos60° ) ....................(i )
=> Fy = Fr ( Sin60° ) ..................(ii )
from equation ( i ) we can take out Resultant Force ( Fr )
Here - Fx = 50 N
=> 50 N = Fr ( Cos 60° )
=> 50 N = Fr × 1 / 2
★ Fr = 100 N
Resultant Force = 100 N .
Now from eq.( ii ) we can take out y - component of Force .
=> Fy = Fr ( Sin60° )
=> Fy = 100 × ( Sin60° )
=> Fy = 100 × √3 / 2
=> Fy = 50 √3
★ Fy = 86.602 N .
==============================
Hope It helps You ☺
___________________________
- Given in Tye Questions :-
• Angle at which force is acting = 60°
• x - component of force = 50 N
Let x - component of Force be Fx
Let y - component of Force be Fy
Let resultant force be Fr
=> Fx = Fr ( Cos60° ) ....................(i )
=> Fy = Fr ( Sin60° ) ..................(ii )
from equation ( i ) we can take out Resultant Force ( Fr )
Here - Fx = 50 N
=> 50 N = Fr ( Cos 60° )
=> 50 N = Fr × 1 / 2
★ Fr = 100 N
Resultant Force = 100 N .
Now from eq.( ii ) we can take out y - component of Force .
=> Fy = Fr ( Sin60° )
=> Fy = 100 × ( Sin60° )
=> Fy = 100 × √3 / 2
=> Fy = 50 √3
★ Fy = 86.602 N .
==============================
Hope It helps You ☺
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