The force necessary to stop a hammer having a momentum of 25 N-s in 0.05 seconds is
(1) 25 N
(2) 50 N
(3) 1.25 N
(4) 500 N
Answers
Answered by
1
P=mv=m×a×t(a=v/t)
25=m×a×0. 05, F=ma,
ma=25÷0. 05=500N
25=m×a×0. 05, F=ma,
ma=25÷0. 05=500N
Similar questions
Physics,
7 months ago
Science,
7 months ago
Math,
7 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago
Physics,
1 year ago