Physics, asked by humayunbabar2563, 1 year ago

The force of 1200 N act on surface area of 10 cm^2 normal what will be the thrust and pressure on the surface

Answers

Answered by Crytek1512
2
Force = Thrust = 1200 N

Area = 10 cm² = 0.001 m²

Therefore, Pressure = Force/Area

= 1200/0.001 = 1200000 Pa

Hope this Helps!
Answered by duragpalsingh
2

Hey there!

Given,

Force(F) = 1200 N

Area (A) = 10 cm² = 0.001 m²

We know,

Thrust is the force acting normally to a surface.

So, Thrust = 1200 N

And, Pressure = Thrust / Area

                        = 1200 / 0.001

                       = 1200000 Pa

                       = 1.2 × 10⁶ Pa

Hope it Helps You!

Similar questions