The force of 1200 N act on surface area of 10 cm^2 normal what will be the thrust and pressure on the surface
Answers
Answered by
2
Force = Thrust = 1200 N
Area = 10 cm² = 0.001 m²
Therefore, Pressure = Force/Area
= 1200/0.001 = 1200000 Pa
Hope this Helps!
Area = 10 cm² = 0.001 m²
Therefore, Pressure = Force/Area
= 1200/0.001 = 1200000 Pa
Hope this Helps!
Answered by
2
Hey there!
Given,
Force(F) = 1200 N
Area (A) = 10 cm² = 0.001 m²
We know,
Thrust is the force acting normally to a surface.
So, Thrust = 1200 N
And, Pressure = Thrust / Area
= 1200 / 0.001
= 1200000 Pa
= 1.2 × 10⁶ Pa
Hope it Helps You!
Similar questions
Physics,
7 months ago
Social Sciences,
7 months ago
Social Sciences,
1 year ago
Accountancy,
1 year ago
Physics,
1 year ago