the force of 200N acts on a body of mass 40kg for 4s,initially at rest.calculate the:
(a) velocity acquired by the body.
(b) change in momentum of the body.
Answers
Answered by
0
Answer:
Force = mass × Acceleration
200 N = 40 × Acceleration
Acceleration = 200/40
= 5 m/s²
Acceleration = Change in velocity / time
Change in velocity = Final velocity - initial velocity
= x - 0 = x (if we let final velocity to be x)
5 = x / 4
x = 5 × 4 = 20 m/s
Momentum = mass × Velocity
Initial momentum = 0 × 40 = 0kgms⁻¹
Final momentum = 20 × 40 = 800kgms⁻¹
Change in momentum = 800 - 0 = 800Kgms⁻¹
Rate of change of momentum = change in momentum /time
800 / 4 = 200 Kgms⁻²
Explanation:
hope its help ✌️✌️
plz mark me as brainliest ❣️❣️
Similar questions
English,
4 months ago
English,
4 months ago
Computer Science,
4 months ago
Chemistry,
9 months ago
Science,
1 year ago
Accountancy,
1 year ago