Physics, asked by rshrivas722, 9 months ago

the force of 200N acts on a body of mass 40kg for 4s,initially at rest.calculate the:
(a) velocity acquired by the body.
(b) change in momentum of the body.​

Answers

Answered by pubgqueen
0

Answer:

Force = mass × Acceleration

200 N = 40 × Acceleration

Acceleration = 200/40

= 5 m/s²

Acceleration = Change in velocity / time

Change in velocity = Final velocity - initial velocity

= x - 0 = x (if we let final velocity to be x)

5 = x / 4

x = 5 × 4 = 20 m/s

Momentum = mass × Velocity

Initial momentum = 0 × 40 = 0kgms⁻¹

Final momentum = 20 × 40 = 800kgms⁻¹

Change in momentum = 800 - 0 = 800Kgms⁻¹

Rate of change of momentum = change in momentum /time

800 / 4 = 200 Kgms⁻²

Explanation:

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