the force of 60N acts on a charge of 15*10^-2 C calculate the value of electric field intensity at the point.
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Explanation:
It is given in the problem that a force of 2.25 N acts on a charge of 15×10-4C. Put F= 2.25 N and . Therefore, the intensity of the electric field is 1500 N/C.
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Answer: Electric field ,E=f/q ,by this formula you can solve this ,
okay........
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