the force of atraction between twomasses m1 and m2 in medium air with seperation d is xapital F then calculate value of force if both m1 and m2 becomes halved 2: when didtance doubled 3: distance becomes halved 4: medium changes to water
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ANSWER
According to Sir Newton's gravitational law the magnitude of gravitational force F between objects of mass m
1
and m
2
separated by a distance R is given by ,
F=G
R
2
m
1
m
2
............eq1 ,
now if the distance between them is doubled i.e. 2R ,then the gravitational force will be ,
F
′
=G
(2R)
2
m
1
m
2
=G
4R
2
m
1
m
2
,
now by using eq1 ,
F
′
=F/4
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