the force of attraction between the charges +0.4mC and -0.8mC is 2N. Find the distance between them.
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F=k×q1×q2/r^2 here f is 2 N and k is 9×10^9 ,q1 is 0.4mc (0.4×10^-3) and q2 is -0.8mc(0.8×10^-3) Then put the value in formula,, 2=9×10^9×0.8×04×10^-6/r^2 then r^2=2.88×10^3/2 ,, r^2=1.44×10^3 , r^2=1440 then r is √1440 means r =37.94 m
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