Question

the force of attraction between the two bodies at a certain separation is 10 Newton what will be the force of attraction between them with the separation is equal to half

Answer 1

Given:

Gravitational attraction force between two bodies at a certain separation is 10 N.

To find:

New force of attraction is the distance between them is halved.

Calculation:

Initial Case:

$force = \dfrac{G(m1)(m2)}{ {d}^{2} }$

$= > \dfrac{G(m1)(m2)}{ {d}^{2} } = 10$

Final case :

New distance distance of separation be d/2.

$force = \dfrac{G(m1)(m2)}{ {( \frac{d}{2} )}^{2} }$

$= > force =4 \times \bigg \{ \dfrac{G(m1)(m2)}{ {d}^{2} } \bigg \}$

$= > force =4 \times \bigg \{10 \bigg \}$

$= > force =40 \: N$

So new gravitational force of attraction will be 40 N.

After reducing the the separation to half of its initial distance, the gravitational force becomes 4 times the initial force.

Answer 2

Explanation:

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