Question

the force of attraction between two bodies at a certain separation is 10 N . What will be the force of attraction between them if the separation is reduced to half

Answer 1

Answer:

since we know that by NEWTON'S GRAVITATIONAL LAW THAT

F=GMm/R^2

so if R1=R/2

Then F becomes 4F

so the answer is (4×10)=40N

Answer 2

Answer:New force of attraction will be enhanced by 4 times.

Explanation:

We know ,F= GMm/r^2

Let F=10 N at separation=r

Now when separation is reduced to half then r'=(r/2)

Now, F'= [G M m/(r/2)^2]

Or, F'= 4GMm/r^2

Or, F'=4F=4×10=40N

Hence the force of attraction will be enhanced by 4 times .