Question

the force of attraction between two bodies at a certain separation is 10N. what will be the force of attraction between them if the separation is reduced to half​

Answer 1

Answer:

Force of attraction will be 40N

Explanation:

F₁ = 1/d²

[Inverse square law]

F₂ = 1/(d/2)²

= 1/(d²/4)

= 4/d²

Therefore,

F₁ : F₂ = 1/d² : 4/d²

= 1 : 4

Therefore,

10:x = 1:4

so,

x = 40N

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