the force of attraction between two bodies at certain seperation is 10N .what will be the focus of attraction between them of the seperation is reduced to half?
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Answer:
force of attraction. will increases 4times then it was before
F is inversely proportional to distance
f \alpha 1 \div \: rfα1÷r
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Answer: the force of attraction is inversly propotional to the square of distance between the objects so,if distance of saperation is reduced to half then the force will get quadrapulled so, the force between the objects is 40n now
Explanation:
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