Question

The force of attraction between two bodies of masses 1 gram each separated by a distance of 1 metre is

Answer 1

Answer:

6.67259 x 10-17 N

Explanation:

F=Gm1m2/r2

where G is gravitational constant

G= 6.67259 x 10-11 N m2/kg2

F= (6.67259 x 10-11 × 0.001×0.001 ) / 1×1

F= 6.67259 x 10-17 N

Answer 2

Given :

Mass of two bodies (m) = 1 gm

Distance of separation between the bodies = 1 m

To Find :

Force of attraction between two bodies

Solution :

The force of attraction between the two bodies of mass 'm₁' and 'm₂' can be given as -

  Force of attraction (F) = $\frac{Gm_1m_2}{r^2}$

where, G = Gravitational constant = 6.67 × 10 ⁻¹¹ N. m². Kg⁻²

            r  = Distance between the bodies

Here, m₁ = m₂ = 1 gm = 0.001 Kg

Thus,
Force of attraction (F) = $\frac{6.67 * 10 ^-^1^1 * 0.001 * 0.001}{1^2}$

                                    = 6.67 × 10⁻¹⁷ N

Therefore, the force between the bodies of mass 1 gm kept at a distance of 1 m is 6.67 × 10⁻¹⁷ N