The force of attraction between two bodies varies directly with the product of their masses when the distance between them is constant and varies inversely with the square of the distance when the product of their masses is constant. The force of attraction between two bodies whose product of masses is 128 and are separated by 4 units is 512. If the product of the masses changes to 64 and the distance between them becomes 8 units, the force of attraction between them becomes “____________
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Answer:
F
g
=G.
r
2
m
1
×m
2
=10 N
where, F= Gravitational force
m
1
,m
2
= Masses of two bodies
r= Distance
G=Gravitaional constant =6.673×10
−11
Nm
2
kg
−2
From the above equation we can conclude that if distance between the object is reduceed to half then force would become four times.
F
g
′
=G.
r
2
/4
m
1
×m
2
Therefore, F
g
′
=4×F
g
So, new force =40 N
Explanation:
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