The force of attraction between two identical charges is 60 N. If the amount of charge is increased to twice of its initial, what will be the force now?
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Answer:
Let the distance between the charges initially be r.
Thus initial electrostatic force F
o
=
r
2
kQ
1
Q
2
New distance between the charges r
′
=3r
Charge of each particle is tripled Q
1
′
=3Q
1
and Q
2
′
=3Q
2
∴ New electrostatic force F
′
=
(3r)
2
k(3Q
1
)(3Q
2
)
=F
o
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