The force of attraction between two magnets is inversely proportional to the square of the distance between them. When the magnets are r cm apart, the force of attraction between fhem is F newtons (N). If the distance between the magnets is increased by 400%, the force of attraction between them becomes cF N. Find the value of c.
Answers
Answer:
c is 200
Step-by-step explanation:
attraction between fhem is F newtons (N). If the distance between the magnets is increased by 400%
it half
Answer:
F=k/d^2
FN=k/r^2
k=FNr^2
use k in the second one.
if the distance is increased 400%, then (increase-original amount)/original amount =4, so the new distance is 5 times the first.
cFN=k/(5r)^2, or FNr^2/25r^2, because the 5 has to be squared as well. The new r is 5r, and (5r)^2=25r^2.
cFN=FN/25
c=1/25
This is inverse square law
To me, there is some ambiguity in an increase of 400% and the distance is increased four-fold, which would be 1/16. If the two distances were initially 2 cm apart, then a four-fold increase makes them 8 cm apart. That is an (8-2)/2 or a 6/2 % increase or 300%.
Step-by-step explanation: