The force of attraction between two objects of masses 2m amd m is F₁.When the object with mass 2m is replaced with another object of mass m/2 ,the new force of attraction is found to be F₂.The ratio of F₁:F₂ IS:- (A)3:2 (B)2:3 (C)1:4 (D)=4:1 ⇒SPAMMER ARE REQUESTED TO STAY AWAY ⇒Need detailed answer from physics newton and other best user :)
Answers
Answered by
0
Explanation:
For the 2nd case :
We have :
→ 1st mass = m/2
→ 2nd mass = m
→ Gravitational force = F2
→ Distance between the masses = r
Vol 85
Again by the law of Gravitation, we have the 2nd equation as :
F₂ = (G x m/2 x m)/r²
F₂ = (Gm²/2)/r²
→ F₂ = Gm²/2r²
-(2)
On dividing eq.1 by eq.2, we get :
F₁/F₂ = (2Gm²/r²) + (Gm²/2r²)
F₁1/F₂ = 2Gm²/r² x 2r²/Gm²
F₁/F₂ = (2 x 2)/1
F₁1/F₂ = 4/1
F₁: F₂ = 4:1
Answered by
0
Answer:
Refer the attachment
Explanation:
Hope it helps you
Mark me as the brainliest and follow
Attachments:
Similar questions