Question

the force of friction between the surface of a floor and the surface of a box with the contact force is 2,000N we wish to move the box on the floor with the constant velocity how much force has to be applied on the box? ​

Answer 1

Answer:

$\huge {\red{\boxed{box}}}$$\huge{\pink {\sf\underline{Step\: by\: step\: explanation}}}$$\bold {\pink{\green {\sf\underline{R1= 8a - 1 = 8*1 - 1={\boxed {7}}}}}}$$\:\:\:\:\:\:\:{R1\:\:\:\:=\:\:\:\:R2}$$\huge{\pink{\green {\sf\boxed{ANSWER}}}}$$\Large\boxed{ANSWER}$

Answer 2

Answer:

To move the box with constant velocity,means with zero acceleration,the net force on it must be zero.

An equivalent force to frictional force should be applied.

Then it should be 2000N

Explanation: