Physics, asked by Harish7852, 1 year ago

The force of gravity on the moon is 1/6 as large as on the earth. how does free-fall acceleration on the moon compare with free-fall acceleration on the earth? free-fall acceleration will be

a.the same on the earth and moon

b.6 times larger on the moon

c.1/3 as large on the moon

d.1/6 as large on the moon.

Answers

Answered by RahulRajYadav
3
option b is right answer
Answered by lidaralbany
1

Answer:

The free-fall acceleration on the moon compare with free-fall acceleration on the earth is \dfrac{1}{6} as large on the moon.

d is correct.

Explanation:

Given that,

The force of gravity on the moon is 1/6 as large as on the earth.

F'=\dfrac{F}{6}

Using newton's second law

The force on the earth

F = ma

Where,

F = force on the earth

a = acceleration due to gravity on the earth

The force on the moon

F' = ma'

Where,

F' = force on the moon

a' = acceleration due to gravity on the moon

The ratio of the force on the earth and on the moon

\dfrac{F}{F'}=\dfrac{ma}{ma'}

\dfrac{F}{\dfrac{F}{6}}=\dfrac{a}{a'}

a'=\dfrac{a}{6}

The acceleration on the moon is \dfrac{1}{6} times of the earth.

Hence, The free-fall acceleration on the moon compare with free-fall acceleration on the earth is \dfrac{1}{6} as large on the moon.

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