Question

The force of repulsion between two charges +2c and +6c is 12n, when charge q is added to both the force of attaraction between them will be 4n

Answer 1

Answer:

i will give you in an example

Explanation:

Two point charges are +2 and +6 repel each other with a force of 12N. If a charge of -4 is given to each of these charges, what will be the force now?

In the first case, using Coulomb's law, we have,

12= k (2)(6)/r^2. OR

r^2= k…..(1)

k is constant appearing in Coulomb's law. k=9x10^9 Nm^2/C^2.

In second case, F=k(-2)(2)/r^2.

Using equation (1),

F=-4N.

Minus sign shows attraction