The force of repulsion between two point charges
is F, when these are 1 m apart. Now the point
charges are replaced by conducting spheres of radii
5 cm having the charge same as that of point
charges. The distance between their centres is 1,then force of repulsion will:
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Answer:
force of repulsion will be same.
Explanation:
F=kq1q2/r²
Force depends on the magnitude of both the charges, not on the size of the charges. Since the magnitude of the charges are same, it will have no effect in the force. Also, force depends on separation distance. Since the distance is same, there is no effect on the force. Therefore, the force will remain the same.
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