The force of repulsion, F newtons (N), between two
particles is inversely proportional to the square of
the distance, d m, between the particles.
(i) Write down a formula connecting F and d.
(ii) When the particles are a certain distance apart,
the force of repulsion is 20 N. Find the force
when the distance is halved.
Answers
Answered by
10
Answer:
(i) F=kQ1Q2/d^2 .......(ii) The force of repulsion would be 80N.
Step-by-step explanation:
As,from formula (i) u can see that F is inversely proportional to d.So by keeping the other parameters constant the new force would be inversly prop. to d^2.Thus,if distance would be halved then the force would be doubled but due to square,if the distance would be halved then force would be quadrupled.
Hopefully u would have got me.
Answered by
8
Answer: 80 N
Step-by-step explanation:
F ∝ 1/D²
=> F = k/D²
Let say at distance = 2x the force of repulsion = 20N
=> 20 = k/(2x)²
=> k = 80x²
The force when the distance is halved is 80 N
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