The force on a phonogram needle is 1.2 N. The point has a circular cross-section of radius 0.1mm. What pressure does it exert on the record in (i) Pa (ii) atm ?
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The force on phonogram needle is, F = 1.2 N. The point has a circular cross section of radius, r = 0.1mm = 10-4 m ⇒ Area = π r2 = 3.14 × 10-4 m2 Pressure = F/A Please substitute the values from above and get the desired answer
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